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Simplifying x2 + 32x + 100 = 0 Reorder the terms: 100 + 32x + x2 = 0 Solving 100 + 32x + x2 = 0 Solving for variable 'x'. Begin completing the square. Move the constant term to the right: Add '-100' to each side of the equation. 100 + 32x + -100 + x2 = 0 + -100 Reorder the terms: 100 + -100 + 32x + x2 = 0 + -100 Combine like terms: 100 + -100 = 0 0 + 32x + x2 = 0 + -100 32x + x2 = 0 + -100 Combine like terms: 0 + -100 = -100 32x + x2 = -100 The x term is 32x. Take half its coefficient (16). Square it (256) and add it to both sides. Add '256' to each side of the equation. 32x + 256 + x2 = -100 + 256 Reorder the terms: 256 + 32x + x2 = -100 + 256 Combine like terms: -100 + 256 = 156 256 + 32x + x2 = 156 Factor a perfect square on the left side: (x + 16)(x + 16) = 156 Calculate the square root of the right side: 12.489995997 Break this problem into two subproblems by setting (x + 16) equal to 12.489995997 and -12.489995997.Subproblem 1
x + 16 = 12.489995997 Simplifying x + 16 = 12.489995997 Reorder the terms: 16 + x = 12.489995997 Solving 16 + x = 12.489995997 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + x = 12.489995997 + -16 Combine like terms: 16 + -16 = 0 0 + x = 12.489995997 + -16 x = 12.489995997 + -16 Combine like terms: 12.489995997 + -16 = -3.510004003 x = -3.510004003 Simplifying x = -3.510004003Subproblem 2
x + 16 = -12.489995997 Simplifying x + 16 = -12.489995997 Reorder the terms: 16 + x = -12.489995997 Solving 16 + x = -12.489995997 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + x = -12.489995997 + -16 Combine like terms: 16 + -16 = 0 0 + x = -12.489995997 + -16 x = -12.489995997 + -16 Combine like terms: -12.489995997 + -16 = -28.489995997 x = -28.489995997 Simplifying x = -28.489995997Solution
The solution to the problem is based on the solutions from the subproblems. x = {-3.510004003, -28.489995997}
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